Differentiate with respect to x y=(x^3)ln2x

To be able to differentiate this we need to use the product rule as we want to differentiate two functions multiplied together. The product rule states that if y=uv, then : dy/dx= u dv/dx + v du/dx. Let u= x^3 and v= ln2x. Then du/dx= 3x^2 and dv/dx= 2/2x. Putting this together using the formula gives: dy/dx= x^3 * 2/2x + ln2x * 3x^2. This simplifies to dy/dx= 3x^2ln2x+x^2

JP
Answered by Jennifer P. Maths tutor

11937 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the inequality |x - 2sqrt(2)| > |x - 4sqrt(2)|.


Solve the inequality 4x^2​>5x-1


Sketch the graph of f(x) = sin(x). On the same set of axes, draw the graph of f(x)+2, f(2x) and f(-x). By observing your graphs of f(x) and f(x), if f(a)=1, what is the value of f(-a)?


Find the integral of y= e^3x / 1+e^x using calculus.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning