Find the first and second derivatives of: y = 6 - 3x -4x^-3, and find the x coordinates of the line's turning points

dy/dx = -3 +12x^-4 d^2y/dx^2 = -48x^-5

MS

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∫ (ln(x)/(x*(1+ln(x))^2) dx


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How do you integrate ln(x) with respect to x?


Simplify (3x^2 - 6x)/ (6x^3 - 19x^2 + 9x +10)