Differentiate f(x) = (x+3)/(2x-5) using the quotient rule.

For a quotient f(x) = u(x)/v(x), the derivative is f'(x) = (vu'(x) - uv'(x))/v(x)2. Applying this to the given function, we find u(x) = x+3 and v(x) = 2x-5. So, u'(x) = 1 and v'(x) = 2. We can then put these into the expression for the quotient rule: f'(x) = ((2x-5)*1 - (x+3)*2)/(2x-5)= (2x - 5 - 2x - 6)/(2x-5)2 = -11/(2x-5)2.

SR
Answered by Sara R. Maths tutor

5417 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

solve the simultaneous equation; x^2+y^2=10 2x+y=5


Integrate cos^2x + cosx + sin^2x + 3 with respect to x


The finite region S is bounded by the y-axis, the x-axis, the line with equation x = ln4 and the curve with equation y = ex + 2e–x , (x is greater than/equal to 0). The region S is rotated through 2pi radians about the x-axis. Use integration to find the


Given that: y = 5x^3 + 7x + 3. What is dy/dx? What is d^2y/dx^2?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning