Differentiate f(x) = (x+3)/(2x-5) using the quotient rule.

For a quotient f(x) = u(x)/v(x), the derivative is f'(x) = (vu'(x) - uv'(x))/v(x)2. Applying this to the given function, we find u(x) = x+3 and v(x) = 2x-5. So, u'(x) = 1 and v'(x) = 2. We can then put these into the expression for the quotient rule: f'(x) = ((2x-5)*1 - (x+3)*2)/(2x-5)= (2x - 5 - 2x - 6)/(2x-5)2 = -11/(2x-5)2.

SR
Answered by Sara R. Maths tutor

5250 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x)=6/x^2+2x i) Find f'(x) ii) Find f"(x)


How do I find the distance between two point in the plane?


Find the centre coordinates, and radius of the circle with equation: x^2 + y^2 +6x -8y = 24


Find the equation of the normal to the curve 2x^3+3xy+2/y=0 at the point (1,-1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences