Find the area under the curve y = sin(2x) + cos(x) between 0 and pi/2
to find the area integrate the function between 0 and pi/2:
indefinite integral of y = -1/2 cos(2x) + sin(x) + c
ignore c and input boundary conditions:
[-1/2 cos(pi) + sin(pi/2)] - [-1/2 cos(0) + sin(0)] = [1/2 + 1] - [-1/2 + 0] = 2
HD
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