Find the area under the curve y = sin(2x) + cos(x) between 0 and pi/2

to find the area integrate the function between 0 and pi/2:

indefinite integral of y = -1/2 cos(2x) + sin(x) + c

ignore c and input boundary conditions:

[-1/2 cos(pi) + sin(pi/2)] - [-1/2 cos(0) + sin(0)] = [1/2 + 1] - [-1/2 + 0] = 2

HD

Related Maths A Level answers

All answers ▸

Core 3 - Modulus: Solve the equation |x-2|=|x+6|.


Find the coordinates of the turning points of the curve y = 4/3 x^3 + 3x^2-4x+1


How do you integrate (2x)/(1+x^2) with respect to x?


How do polar coordinate systems work?