Integrate with respect to x ) dy/dx= 6x^5
The integral of any equation let the example be dy/dx = ax^n The integral of (RHS) dy/dx (because when we integrate we are integrating both sides) is y The integral of (LHS) ax^n is [ax^(n+1)]/[n+1] when integrating there is always a constant that is unknown without any other equations that hold. Thus the integral is y= [ax^(n+1)]/[n+1] +C (Where C is a currently unknown constant)
NM
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