Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37
taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)2 +4y2=37 Expand and simplify: y2 +8y+16+4y2=37 5y2+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3
AW
Related Maths GCSE answers
All answers ▸Given a circle with the equation y^2 + x^2 = 10, with a tangent that intersects at point P, where x=1, find the coordinates for the point at which the tangent meets the x axis (Q).
Solve this quadratic equation 3x(squared)-7=101
How would you solve the simultaneous equations y=x+1 and y=4x-2
Solve the equation: x^2 +8x + 12 = 0