Solve the equation [(3x + 3)/2x] + 2x - 1 = -3

In this question we are trying to find all the possible solutions of the variable x that will satisfy the given equation. Firstly, we see there is a denominator on one of the terms so we multiply all the terms in the equation by this denominator so as to simplify it. Next we can multiply the brackets out and bring all the terms to one side, while paying careful attention to the changes in signs. Now we have a quadratic equation and the simplest way to solve this is break up the x term and find a common bracket. Once we have done this we can easily solve for x, getting the ansers -1 and -3/4. Below is a step by step example of the process.

[(3x + 3)/2x] + 2x - 1 = -3

(3x + 3) + (2x)(2x - 1) = (2x)(-3)

3x + 3 + 4x2 - 2x = -6x

4x2 + 7x + 3  = 0

4x2 + 4x + 3x + 3 = 0

4x(x + 1) + 3(x + 1) = 0

(x + 1)(4x + 3) = 0

x = -1 or x = -3/4

CB
Answered by Chris B. Maths tutor

3292 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4


Solve 2x^2 + 6x + 4 = 0 for x using the quadratic formula.


How do you find the area of a sector of a circle if you know the radius and the angle in the centre?


Solve these pair of simultaneous questions: 3x+2y=17 4x-y=30


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning