simplify (2q+4)/(p(p+1)) -q/p
times the whole equation by the denominator of the left fraction giving p(2q+4)(p+1) - (qp(p+1))/p
notice that p can be cancelled in the right fraction, and then times out to give
2qp^2 + 4p + 4p^2 + 2pq - qp + q
This can be factorised in this way
p(2p(q+4)+(q+4))+q
and then further
p(q+4)(2p+1)+q
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