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differentiate y = 4x^3(12e^-4x) with respect to x

y = 4x³e^-4x u = 4x³ v = e^-4x du/dx = 12x² dv/dx = -4e^-4x using the product rule; vdu +udv vdu + udv = 12x²e^-4x- 16x³e^-4x

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Answered by Lewis M. • Maths tutor

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