Answers>Maths>A Level>Article

differentiate y = 4x^3(12e^-4x) with respect to x

y = 4x³e^-4x u = 4x³ v = e^-4x du/dx = 12x² dv/dx = -4e^-4x using the product rule; vdu +udv vdu + udv = 12x²e^-4x- 16x³e^-4x

LM

Answered by Lewis M. • Maths tutor

3958 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

how do integrate an equation with a surd or a fraction?

How would you differentiate f(x) = 2x(3x - 1)^2 using the chain rule?

What is the partial fraction expansion of (x+2)/((x+1)^2)?