Given the function f(x) = (x^2)sin(x), find f'(x).

The function f(x) is a product of 2 functions of x, so when we differentiate it, we need to use the product rule.

The product rule states that for a function f(x) = g(x)*h(x), f'(x) is given by g(x)*h'(x) + h(x)*g'(x).

If we break f(x) up into two parts and let g(x) = x2 and h(x) = sin(x) then we can find g'(x) and h'(x).

We find that g'(x) = 2x and h'(x) = cos(x). Substituting these values into the product rule, we get:

f'(x) = x2cos(x) + 2xsin(x).

Answered by Jason S. Maths tutor

7554 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The point A lies on the curve y=5(x^2)+9x , The tangent to the curve at A is parralel to the line 2y-x=3. Find an equation to this tangent at A.


The Curve C has equation y = 3x^4 - 8x^3 -3. Find the first and second derivative w.r.t x and verify that y has a stationary point when x = 2. Determine the nature of this stationary point, giving a reason for your answer.


The equation of a line is y=3x – x^3 a) Find the coordinates of the stationary points in this curve, stating whether they are maximum or minimum points b) Find the gradient of a tangent to that curve at the point (2,4)


Solve for x, between 0 and 360 degrees, 4cos2 (x) + 7sin (x) – 2 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy