Find the roots of y=x^{2}+2x+2
y=x2+2x-3
Can solve using quadratic equation. Using the square method to obtain for the square term and x term (x+1)(x+1) = x2+2x+1
Therefore (x+1)(x+1)-4=y
To find roots equate to zero: (x+1)(x+1)-4=0
Therefore: (x+1)2=4
Which implies that: x+1=+/-2
Therefore roots are x=-3 and x=1
Input these into the original equation to check and will see that these are correct.
