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Differentiate 4x^2 + 2ln3x + e^x

To differentiate x2 you bring the power of x down, then reduce the power of x by 1, so d/dx(x2) = 2x1

ln3x differentiates to (d/dx(3x))/3x = 3/3x = 1/x

e^x differentiates to (d/dx(x))*e^x = 1*e^x

Therefore, d/dx(4x2 + 2ln3x + ex) = 4(2x) +2(1/x) + ex = 8x + 2/x + ex

Thomas M. GCSE Maths tutor, A Level Maths tutor

2 years ago

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