The line l1 has equation y = −2x + 3. The line l2 is perpendicular to l1 and passes through the point (5, 6). (a) Find an equation for l2 in the form ax + by + c = 0, where a, b and c are integers.

The first thing to look at is l2 and l1 being perpendicular. This means the gradients of the two lines multiplied together = -1 . To determine the gradient a student could differentiate l1 but a slightly quicker way is using just using y = mx+c , spotting -2 is equivalent to m which is also equivalent to the gradient. Using l1's gradient and the fact the two lines are perpendicular l2 can be calculated to equal 0.5. This can then be placed into y = mx+c and then to find out c the point (5,6) will be subbed in. the final equation for l2 is 2y -x - 7 = 0 

RP
Answered by Roman Paul M. Maths tutor

15822 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do we work out the asymptotes of the graph y=1/x -5


Differentiate the equation y = x^2 + 3x + 1 with respect to x.


Find the turning value of the following function, stating whether the value is min or max, y = x^2 -6x + 5


differentiate: y^2 + 3xy + x + y = 8


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences