Solve these simultaneous equations, 2x+y=6 and 3y-x=11

First step is to choose between the three methods for solving simulataneous equations; elimination, substitution and eqaulity. In this case the best method is probably substitution, but personal preference is reasonable.  By rearranging the second equation to find an expression for x we get; x=3y-11. Substituting this into the first equation gives 2(3y-11)+y= 6y-22+y=7y-22=6. Add 22 to both sides for 7y=28 and hence by dividing both sides by 7, we obtain y=4.  Substitute this into either equation and solve, eg, 2x+4=6 gives x=1. Therefore the solution is x=1 and y=4.

EG
Answered by Edward G. Maths tutor

4354 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve the simultaneous equation: 3x+y=7, 2x+4y=8


What are the roots of (2x-5)(x-3) = 0


Bob and Bill have 50 sweets to share in the ratio 4:6 respectively. how many do they each get?


Solve the simultaneous equations: 3x-y=1, x^2+y^2=5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences