Given that x = ln(sec(2y)) find dy/dx

x = ln (sec (2y))

The chain rule states that d/dy f (g (y)) = f'(g(y)). g'(y)

Here g(y) = sec(2y) so g'(y) = 2.sec(2y).tan(2y)

And f(y) = ln (y) so f'(y) = 1 / y

Thus dx/dy = (1 / sec(2y)) . (2.sec(2y).tan(2y)) = 2.tan(2y)

DH
Answered by Dom H. Maths tutor

12032 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find the angle between 2 vectors?


Polynomial long division, how do I do it?


In a geometric series, the first and fourth terms are 2048 and 256 respectively. Calculate r, the common ratio of the terms. The sum of the first n terms is 4092. Calculate the value of n.


What is (5+3i)*(3+5i)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences