P=(3a+5)/(4-a) Make a the subject

P=(3a+5)/(4-a)First of all we need Get rid of the denominator, we do this by multiplying both sides by (4-a)This leaves P(4-a)=3a+5 (as any term multiplied by the denominator leaves only the numerator)The next step is to expand the bracket, which leaves us with 4P-aP=3a+5.Now we need to put all "a" terms on one side of the equation and all "non a" term on the other. To do this we can add aP to both sides and minus 5 to both sides. This leaves us with 4P-5=3a+aP.Now we have a as a common term on the right side so we can factorise to move a outside of the bracket leaving 4P-5=a(3+P)Now the final step is to divide both sides by (3+P) to leave a as the subject.This leaves us with the final correct answer of (4P-5)/(3+P)=a

JS
Answered by Joshua S. Maths tutor

4220 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation "3y + 5 = 11" to find the value of y.


Show that (x+2)(x+3)(x+4) can be written in the form of ax^3+bx^2+cx+d where a, b, c and d are positive integers.


Michael is saving for new iPhone. He gets £30 as pocket money per week, however he spends 20% of the whole amount for leisure and his savings only consists of the residue amount. If an iPhone costs £600 how many weeks would Michael need to save for it?


how do ratios work


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning