How do you know if the second derivative of an equation is a maximum or a minimum?

If the second derivative of an equation is positive (d2y /dx2 > 0), we can see that this point on a curve is a minimum. This is because, where the first derivative finds the gradient of a curve (how the slope changes with respect to a change in x), the second derivative finds how an increase in x of an incremental amount affects the change in the gradient. - if you imagine y=x2, for example, we know it looks like a U so has a minimum point - any increase in x from the minimum (move to the right) would lead to the gradient increasing, so is positive. (The first derivative of x2 is 2x, the second derivative is 2 (positive)).
Conversely it follows that if the second derivative is negative (d2y /dx2 < 0), the curve has a maximum because any increase in x of any tiny amount will lead to the gradient decreasing (getting more negative away from zero) - so the change in the gradient will be negative. For y = -x2 , which looks like an upside down U, the first derivative is -2x, and the second is -2 which shows there to be a maximum (which we know is true).

JG

Related Maths A Level answers

All answers ▸

differentiate y=(4x^3)-5/x^2


The point A lies on the curve y=5(x^2)+9x , The tangent to the curve at A is parralel to the line 2y-x=3. Find an equation to this tangent at A.


Solving harder exponential equations, e.g. 5/[exp(x) + 6exp(-x)] - 1 = 0 . CORE MATHS.


How do you differentiate a function comprised of two functions multiplied together?