2x+y=18, x-y=6; Solve the simultaneous equations

  1. 2x+y =182) x-y =6(x-y=6) multiply by +22x-2y = 121) 2x+y = 182) 2x-2y=12 -subtract equation 2 from equation 10x-y=6 -Therefore -y=6 so y= -6Put value for y into either of the equation in order to find value for xSo: 2x + (-6) = 18 2x - 6 = 18 2x = 24 x = 24/2 x = 12Therefore x=12, y=-6
SW
Answered by Saskia W. Maths tutor

4896 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Using Pythagoras theorem to find side lengths of a triangle


Define a surd and find the length of one side of a 50cm^2 square shape in surd form


How do you convert between fractions, decimals and percentages?


Solve the Simultaneous Equations -3X + 4Y=11 & X-2Y = -5 to find the values of X and Y


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences