2x+y=18, x-y=6; Solve the simultaneous equations

  1. 2x+y =182) x-y =6(x-y=6) multiply by +22x-2y = 121) 2x+y = 182) 2x-2y=12 -subtract equation 2 from equation 10x-y=6 -Therefore -y=6 so y= -6Put value for y into either of the equation in order to find value for xSo: 2x + (-6) = 18 2x - 6 = 18 2x = 24 x = 24/2 x = 12Therefore x=12, y=-6
SW
Answered by Saskia W. Maths tutor

5319 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the square of an odd number is always 1 more than a multiple of 4


How do I solve the simultaneous equations x-2y=1 and x^2-xy+y^2=1?


There are 3 red beads and 1 blue bead in a jar. A bead is taken at random from the jar. what is the probability that the bead is blue?


A(0,2) and B(6,5) are two points on the straight line ABCD. If AB=BC=CD find the coordinates of the point D


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning