Solve the simultaneous equations (1) 2x+3y=3 and (2) 3x+2y=7
Remember we can multiply both sides of an equation by the same thing without changing the meaning of the equation. Multiplying equation 1 by 2 gives 4x+6y=6 and multiplying equation 2 by 3 gives 9x+6y=21 . Subtract equation 1 from equation 2 to eliminate y. This gives 5x=15 => x=3Substitute x=3 back into one of the original equations to find y. For example, 2(3)+3y=3 => y=-1
ZL
Related Maths GCSE answers
All answers ▸HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts
How do you factorise quadratic equations by completing the square?
Find the inverse of y = 2x+1/ x-1
A ladder 5.5m long is leaning against a wall. the foot of the ladder is 1.7m away from the wall. how far up the wall does the ladder reach?