Solve the simultaneous equations (1) 2x+3y=3 and (2) 3x+2y=7

Remember we can multiply both sides of an equation by the same thing without changing the meaning of the equation. Multiplying equation 1 by 2 gives 4x+6y=6 and multiplying equation 2 by 3 gives 9x+6y=21 . Subtract equation 1 from equation 2 to eliminate y. This gives 5x=15 => x=3Substitute x=3 back into one of the original equations to find y. For example, 2(3)+3y=3 => y=-1

ZL

Related Maths GCSE answers

All answers ▸

Solve the quadratic equation x^2+5x+6=0


Prove that the difference between the squares of any two consecutive integers is equal to the sum of these two integers.


If I put £500 in the bank with an annual interest rate of 3% how much money will I have earned in 2 years?


Factorise and solve x^2 - 8x + 15 = 0