Solve the linear simultaneous equations: 3x + 5y = 45, 2x - 9y = -7

x = 10, y = 3. From the second equation, we have x = (9y - 7)/2. Substituting this expression for x into the first equation gives 3(9y - 7)/2 + 5y = 45. 3(9y - 7) + 10y = 90. 27y - 21 + 10y = 90. 37y = 111. y = 111/37 = 3. Finally, substituting our result for y into our expression for x gives x = (27 - 7)/2 = 20/2 = 10

CW
Answered by Cameron W. Maths tutor

3352 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

You are shown a diagram of a right angled triangle, with the hypotenuse labelled c and the other sides labelled a and b. If a is 7m long and c is 10m long, what is the length of b?


y is inversely proportional to x. y = 0.04 when x = 80. Find the value of y when x = 32.


Rationalise the denominator of 1/(4 + sqrt(3))


Factorize x^2 + 4x -5 and hence find the roots of the quadratic equation y = x^2 + 4x - 5.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences