Integrate the function f(x) = 1/(4x-1)
t Using the fact that d/dx ( ln g(x)) = g'(x)/g(x), we can see that the integral of this function will be an ln function. From observing f(x) we see that if the answer was ln(4x-1) then f(x) would need to be 4/(4x-1). This is four times bigger than what we want. To obtain the correct integral, we simply multiply ln(4x-1) by 1/4 to get rid of the 4 in the numerator, and so we arrive at the final answer of 1/4 ln(4x-1)
SV
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