Answers>Maths>A Level>Article

g(x) = e^(x-1) + x - 6 Show that the equation g(x) = 0 can be written as x = ln(6 - x) + 1, where x<6

0 = e^x-1+ x - 6 e^x-1= 6-x x-1 = ln (6-x) -> here we have taken the natural log of both sides, but it only shows on one side as the natural log of e is 1.x = ln (6-x) + 1Question taken from Edexcel 2013 C3 past paper, with my own adapted answer.

Answered by Sumrah N. • Maths tutor

7840 Views

See similar Maths A Level tutors

g(x) = e^(x-1) + x - 6 Show that the equation g(x) = 0 can be written as x = ln(6 - x) + 1, where x<6

Related Maths A Level answers

Solve |3x+1| = 1

How can I remember how to differentiate and integrate cos and sin?

Prove the identity (4cos(2x))/(1+cos(2x)) = 4-2sec^2(x)

Differentiate 2x^3+23x^2+3x+5 and find the values of x for which the function f(x) is at either at a maximum or minimum point. (Don't need to specify which is which)