A curve is defined by the parametric equations x=(t-1)^3, y=3t-8/(t^2), t is not equal to zero. Find dy/dx in terms of t.

We see that x and y are both expressed in terms of t and as we are looking to define dy/dx in terms of t, the first step we take is to find the derivatives of x and y in terms of t as follows.x = (t-1)^3dx/dt = 3(1)(t-1)^{(3-1) .} (By the chain rule) = 3(t-1)²y = 3t - 8t^(-2) (Note that y = 3t - 8t^(-2) to facilitate the use of chain rule)dy/dt = 3 - (8)(-2)t^(-2-1) = 3 + 16t^(-3)Now to find dy/dx, just divide dy/dt by dx/dt as follows.(dy/dt)/(dx/dt) = (3 + 16t^(-3))/3(t-1)² (the dt's cancel out)dy/dx = (3 + 16t^(-3))/3(t-1)² As Required.