The line L has equation y=5-2x. Find an equation of the line perpendicular to L, which passes through the point P (3,-1).
The gradient of the line L is -2 so the gradient of the line perpendicular to L will be the negative reciprocal of -2 which is 1/2.The equation of the line perpendicular to L will be y=mx+c where m is the gradient and c is the y-intercept. When we put in the gradient we've found we get y=1/2x+c. We can find c by substituting in our x and y values from the point P which the line passes through. We get -1=3/2+c so c=-5/2 and therefore the line perpendicular to L has equation y=1/2x-5/2.
KN
Related Maths A Level answers
All answers ▸Solve $\color{orange}{a}x^2 - \color{blue}{b}x + \color{green}{c} = 0$
Find the derivative of the following function: f(x) = x(x^3 + 2x)
Solve the following equation, give the answer/answers as coordinates. y=3x^2 , y=2x+5.
Find the equation of the tangent to the curve y = (2x -3)^3 at the point (1, - 1), giving your answer in the form y = mx + c.