Given the parametric equations x = t^2 and y = 2t -1 find dy/dx
The first step is to find dx/dt and dy/dt, this is done using standard differentiation rules giving the resultsdx/dt = 2t dy/dt = 2
The second step is to eliminate dt. This can be done by the multiplication dy/dt * dt/dx = dy/dx. dt/dx is equivalent to 1/(dx/dt) = 1/(2t), multiply this by dy/dt to find the final answer which is dy/dx = 1/(2t) * 2 = 1/t.
MH
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