Given the parametric equations x = t^2 and y = 2t -1 find dy/dx

The first step is to find dx/dt and dy/dt, this is done using standard differentiation rules giving the resultsdx/dt = 2t dy/dt = 2
The second step is to eliminate dt. This can be done by the multiplication dy/dt * dt/dx = dy/dx. dt/dx is equivalent to 1/(dx/dt) = 1/(2t), multiply this by dy/dt to find the final answer which is dy/dx = 1/(2t) * 2 = 1/t.

MH
Answered by Matthew H. Maths tutor

8727 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the integral of (6x^2 + 2/x^2 + 5) with respect to x?


How do I prove that an irrational number is indeed irrational?


Given the function y = x^5 + x^3/2 + x + 7 Express the following in their simplest forms: i) dy/dx ii) ∫ y dx


When do I use the chain rule and when do I use the product rule in differentiation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences