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Cracking of the unbranched compound E, C6H14, produced the saturated compound F and an unsaturated compound G (Mr = 42). Identify these compounds and write an equation for the reaction.

Compound E is an unbranched alkane. The general formula of an alkane is C_nH_2n+2.Compound E is CH₃CH₂CH₂CH₂CH₂CH₃.Compound G is an unsaturated hydrocarbon or an alkene. The general formula of an alkene is C_nH_2n. To achieve an Mr of 42, the formula of compound G must be C₃H₆.Compound F is an unsaturated hydrocarbon or an alkane. Compound F is C₃H₈.The equation for the cracking reaction is: C₆H₁₄---> C₃H₆+ C₃H₈

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Cracking of the unbranched compound E, C6H14, produced the saturated compound F and an unsaturated compound G (Mr = 42). Identify these compounds and write an equation for the reaction.

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