Solve the following set of simultaneous equations: 3x + y = 11, 2x + y = 8

First I will explain the scenario and clearly describe what exactly the question is asking us to do: in this case, we have to find the correct value of 'x' and 'y' that successfully agree with both of the equations. Explain that, using one equation on its own gives an infinite number of possibilities for x and y values, but in order to satisfy both equations, there will only be one x and one y value. It is also important to note that the most effective and speed of method to solve simultaneous equations vary according to the question and the nature of the equations. For this example, method of Subtraction is the most obvious and easiest method, but I will show how using a different method such as substitution will give the same answer.Line up one equation above the other equation so that the x terms and y terms as well as the + and = signs line up. Show how when the 2x equation is subtracted from the 3x equation, you end up with x + (0y) = 3. We have calculated that x = 3. Substituting back x = 3 into any of the two equations will lead us to finding out what y is. It is wise to show how by using either equation you will end up with the same y equation, thus showing that x = 3 and y = 2 is a solution to both equations. I will further explore this topic, by drawing out the lines of both equations on a Cartesian graph and showing that the two lines intersect at one point, (3,2) as required.

Answered by Sahiththiyan S. Maths tutor

2492 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The area of a square is 49cm^2. The perimeter of this square is equal to the circumference of a circle. Calculate the radius of the circle to 1 decimal place.


How do I solve sequences and how can I get the nth number?


What is the gradient of the graph y = 3x^2 + 5x + 2, when x is 4?


What is the best way to solve simultaneous equations?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy