The first floor of an ancient japanese tower has 150 steps. Each floor above has 5 fewer floors than the previous. So, the second floor has 145 steps, the third 140 etc. How many floors does the tower have if the final floor has 30 steps leading to it.

Note this is an arithmetic series problem, so we use the equation: xn = a + d(n-1).
Number of steps on the first floor is 'a', i.e. a = 150.
Difference in the number of steps on each subsequent floor is -5 because there are '5 fewer than the previous', i.e. d = -5.
We are given that the number of steps leading to the final floor is 30, hence xn = 30.
Our unknown 'n' denotes the number of floors. So rearranging the arithmetic series equation for n gives:
n = (xn - a)/d + 1.
Hence n = (30-150)/(-5) + 1 = 25. The number of floors in our temple is 25.

JF
Answered by Joel F. Maths tutor

2828 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

8^(3/4)*2^(x) = 16^(4/5). Work out the exact value of x.


How do i solve quadratic equations?


Solve the Simultaneous equations. 3x+5y=22 4x-5y=6


The straight line L1 passes through the points with coordinates (4, 6) and (12, 2) The straight line L2 passes through the origin and has gradient -3. The lines L1 and L2 intersect at point P. Find the coordinates of P.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences