Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12

  1. 2x + 3y = 52. 3x + 4y = 12
    Firstly, you want to have the same amount of x variables, or y variables. To get the same x, we multiply 1. by 3, and multiply 2. by 2, giving us:
    3. 6x + 9y = 154. 6x + 8y = 24
    Now, subtract 4. from 3. and you get:y = -9
    Using this information, substitute it into any of the 4 equations, and solve to find x.
    Subbing into 3. gives us:6x + 9(-9) = 156x - 81 = 156x = 96x = 16
QO
Answered by Quincy O. Maths tutor

6632 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

n is an integer greater than 1. Prove algebraically that n^2 – 2 – (n – 2)^2 is always an even number.


x^2-12x+20=0 Find x


The area of a parallelogram is given by the equation 2(x)^2+7x-3=0, where x is the length of the base. Find: (a) The equation of the parallelogram in the form a(x+m)^2+n=0. (b) The value of x.


Find max point of y=-x^2-5x-10


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning