Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12

  1. 2x + 3y = 52. 3x + 4y = 12
    Firstly, you want to have the same amount of x variables, or y variables. To get the same x, we multiply 1. by 3, and multiply 2. by 2, giving us:
    3. 6x + 9y = 154. 6x + 8y = 24
    Now, subtract 4. from 3. and you get:y = -9
    Using this information, substitute it into any of the 4 equations, and solve to find x.
    Subbing into 3. gives us:6x + 9(-9) = 156x - 81 = 156x = 96x = 16
QO
Answered by Quincy O. Maths tutor

6154 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you find the area of a sector of a circle if you know the radius and the angle in the centre?


Simplify fully (3x^2-8x-3)/(2x^2-6x)


Find the possible values of x from the equation 3(x^2)+2x-4=2(x^2)+3x+8


Solve x/(x-7) + 6/(x+4) = 1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning