Given the points (6,6) and (10,8) calculate the gradient of the line passing through them and the point at which it intersects the y-axis?

To find the gradient use the formula:m = (y2-y1)/(x2-x1)Plug in values:m = (8-6)/(10-6) = 1/2Hence gradient = 1/2--Now using the equation for a line y = mx+c and point (10,8)8 = 1/2*10 + cc = 3Hence when the line passes through the x axis, x = 0 and y = c and hence values is 3

GA
Answered by Gilad A. Maths tutor

3514 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Fully simplify: (y^2 x y^5) / y^3


Find the equation of the straight line passing through the points (7,5) and (8, 2)


If we know that y is directly proportional to x and that when x=1, y=3, then what is the value of x when y=4?


A) Multiply out 6(n - 2). B) Factorise psquared - 5p


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences