Given the points (6,6) and (10,8) calculate the gradient of the line passing through them and the point at which it intersects the y-axis?
To find the gradient use the formula:m = (y2-y1)/(x2-x1)Plug in values:m = (8-6)/(10-6) = 1/2Hence gradient = 1/2--Now using the equation for a line y = mx+c and point (10,8)8 = 1/2*10 + cc = 3Hence when the line passes through the x axis, x = 0 and y = c and hence values is 3
GA
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