Given the points (6,6) and (10,8) calculate the gradient of the line passing through them and the point at which it intersects the y-axis?

To find the gradient use the formula:m = (y2-y1)/(x2-x1)Plug in values:m = (8-6)/(10-6) = 1/2Hence gradient = 1/2--Now using the equation for a line y = mx+c and point (10,8)8 = 1/2*10 + cc = 3Hence when the line passes through the x axis, x = 0 and y = c and hence values is 3

GA
Answered by Gilad A. Maths tutor

4062 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What are the two roots for the equation x^2 + 7x + 10 = 0


Simplify 2a^3 b × 5a^2 b^3


expand the brackets: (x+3)(x+2)


What is the method to solve an equation of type : ax^2+bx+c = 0 ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning