A circle with center C has equation x^2 + y^2 + 8x - 12y = 12
Circle equation = (x - a)2 + (y - b)2 = r2Where Centre coordinates (a, b) and radius 'r'Therefore x2 + y2 + 8x - 12y = 12 is to be rewritten in this formComplete the square to find a and bThis gives(x+4)2 - 16 + (y - 6)2 - 36 = 12Simplify(x+4)2 + (y - 6)2 = 64Therefore refering to the top two linesCentre of the circle is (-4, 6) and Radius of the circle is 8
HK
Related Maths A Level answers
All answers ▸How do I differentiate 3^2x?
A curve has equation y = f(x) and passes through the point (4, 22). Given that f ′(x) = 3x^2 – 3x^(1/2) – 7, use integration to find f(x), giving each term in its simplest form.
Differentiate: y = 3x^2 + 4x + 1 -4x^-1
Determine the coordinates of all the stationary points of the function f(x) = (1/3)*x^3+x^2-3*x+1 and state whether they are a maximum or a minimum.