The curve C has the equation ye ^(–2x) = 2x + y^2 . Find dy/dx in terms of x and y.


differentiate both side with respect to x : (dy/dx)e^(-2x)+y(-2e^(-2x)) = 2+2y(dy/dx)
rearrange it : (-2y+e^(-2x))(dy/dy) = 2 + 2ye^(-2x) ==> dy/dx = ( 2 + 2ye^(-2x) ) / ( -2y+e^(-2x) )

JC
Answered by Jimmy C. Maths tutor

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