integrate the following: 2x^4 - 4/sqrt(x) +3 with respect to x

The 3 terms of this equation can be integrated separately. The general integration of xn is (xn+1)/n+1 where n is a real number not equal to -1. This can be applied to the terms 2x4, -4/sqrt(x) and 3 separately. 2x5 becomes (2x5)/5. -4/sqrt(x) can be rewritten as -4x-0.5 which integrates as -4x0.5/(0.5) which can be simplified as -8sqrt(x). Finaly, 3 will become 3x (this is because 3 can be rewritten as 3x0 so will therefore integrate as 3x).
All together this gives the following equation as the solution: (2x5 )/5- 8sqrt(x) +3x + C (don't forget the +C after every integration)

AF
Answered by Adrien F. Maths tutor

3275 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you differentiate a function containing e?


Differentiate y = 15x^3 + 24x^2 + 6 with respect to x.


a typical question would be a setof parametric equations y(t) and x(t), asking you to find dy/dx and then the tangent/normal to the curve at a certain point (ie t = 2)


How do you integrate a fraction when x is on the numerator and denominator?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences