Expand (2x-1)(x+3)

Method 1: Foil method (each term of the first bracket are multiplied by each term of the second bracket, and hence the product have 4 terms before simplifying)(2x-1)(x+3) = 2xx + 2x3 - 1x -13 =2x2 + 6x - x -3 = 2x2 + 5x - 3(* denotes multiply)Method 2: Grid method (the horizontal terms are multiplied with the vertical terms, i.e.: 2x x, -13)* 2x -1x 2x2 -x3 6x -3 Adding the 4 product terms together, we get: 2x2 - x + 6x -3 = 2x2 + 5x - 3

CN
Answered by Cherish N. Maths tutor

13056 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

c is a positive integer. Prove that (6c^3 + 30c) / (3c^2 +15) is an even number.


Solve the simultaneous equation: 2x + y = 18, x - y = 6


how am I meant to solve sq.root(6^2+8^2) = cube.root(125a^3) when one side is squared and the other is cubed?


How to solve the inequality 4(x+3) < 60?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning