Solve the following quadratic: x^2 -5x +6=0

Step 1: factorise Find two numbers which add to make -5 and multiply to make 6--- -3 and -2(x-3)(x-2)=0
Step 2: recognise solutionsTo make the left hand side equal the right hand side, we can make one of the brackets equal zero.When x=3, (3-3)(3-2)=0=RHS  so one solution is x=3
When x=2, (2-3)(2-2)=0=RHS  so the other solution is x=2

RH

Related Maths GCSE answers

All answers ▸

Show that (x + 1)(x + 3)(x + 5) can be written in the form ax^3 + bx^2 + c^x + d where a, b, c and d are positive integers.


If m=a^x, n=a^y, and a^2 =(m^y n^x)^z Show xyz=1.


5y = 45


Explain why the points (0,8) do not lie on the line y= 4x+9 ? (3 marks)