Calculate the relative molecular mass of CaCO3. (relative atomic mass (Ar): C= 12, Ca= 40, O= 16)

Number of atoms
Ca x1 => 40x 1= 40
C x 1 => 12x1 = 12
O x 3= 16 x 3= 48CaCO3
RMM= 40 + 12 + 48= 100

RM
Answered by Roxanne M. Chemistry tutor

25456 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Describe how a metal conducts electricity


What is a catalyst?


why do ionic compounds conduct electricity when in molten state or solution but not when solid?


Lithium and potassium are both in Group 1 of the periodic table. Explain why.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences