Calculate the relative molecular mass of CaCO3. (relative atomic mass (Ar): C= 12, Ca= 40, O= 16)

Number of atoms
Ca x1 => 40x 1= 40
C x 1 => 12x1 = 12
O x 3= 16 x 3= 48CaCO3
RMM= 40 + 12 + 48= 100

RM
Answered by Roxanne M. Chemistry tutor

28232 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What is a catalyst?


State the trends in reactivity of the group 1 and group 7 elements and explain the reasons why.


Balance this equation: C6H12O6 + _O2 --> _CO2 + _H2O


How is crude oil separated into fractions?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning