Calculate the relative molecular mass of CaCO3. (relative atomic mass (Ar): C= 12, Ca= 40, O= 16)

Number of atoms
Ca x1 => 40x 1= 40
C x 1 => 12x1 = 12
O x 3= 16 x 3= 48CaCO3
RMM= 40 + 12 + 48= 100

RM
Answered by Roxanne M. Chemistry tutor

30895 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Why does Iodine have a higher boiling point than chlorine?


What is Le Chatelier's principle and how do you apply it to reversible reactions?


A chemist needs to neutralise aqueous hydrochloric acid solution (currently pH 1) to pH 7 or higher, so it can be safely disposed of. They have access to solid NaCl, NaBr and Na2CO3.


What is an ion and how are they formed?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning