Show that the line with equation ax + by + c = 0 has gradient -a/b and cuts the y axis at -c/b?
This question involves inspecting the answers that have been provided to us. We have been given a constant gradient, and a point at which the line given by the equation cuts the y axis. This, therefore, means that this is a straight line equation, and can be rearranged in the form y = mx + c , where m is the gradient, and c is the y-axis intercept. Moving 'ax' and 'c' to the other side of the equation, and dividing by 'b', we get the straight line equation y = (-a/b)x - c/b . An example of what this straight line graph may look like can be shown on the whiteboard with example values.
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