Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.

To satisfy the condition of substracting two fractions with unlike denominators, a common denominator needs to be found. By recognizing x^2 - 9 = (x-3)(x+3), we can rewrite the question as 4x/(x-3)(x+3) - [2/(x+3)] * [(x-3)/(x-3) ]= [4x-2(x-3)]/[(x+3)(x-3)] = 2(x+3)/(x+3)(x-3) = 2/(x-3)The answer is 2/(x-3).

YC
Answered by Ye C. Maths tutor

6240 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The quadratic equation 2x^2 + 8x + 1 = 0 has roots x1 and x2. Write down the value of x1+x2 and x1*x2 and find the value of x1^2 + x2^2


Prove that the indefinite integral of I = int(exp(x).cos(x))dx is (1/2)exp(x).sin(x) + (1/2)exp(x).cos(x) + C


Find the value of: d/dx(x^2*sin(x))


What is the coefficient of x^2 in the expansion of (5+2x)^0.5?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning