Why does a feather fall at the same rate as a hammer on the Moon?

To calculate an object's weight, we have weight = mass * gravitational field strength (W = mg). From this, we see that an object with a greater mass (e.g. a hammer compared with a feather) has a greater weight, and since weight is the force that causes falling, we might expect that it will fall faster.
However, this does not happen. If we want to work out the acceleration of an object, we use Newton's second law, force = mass * acceleration (F = ma). Since weight is the force acting on the hammer or feather, we can equate our expression for the weight, mg, to ma:
ma = mg
We can then divide both sides of this equation by m, yielding
a = g
And therefore, the acceleration a doesn't depend on m, the object's mass. For this reason, a hammer and a feather will fall with the same acceleration on the Moon, as long as there are no other forces.

JT

Related Physics A Level answers

All answers ▸

If you have 1.33g of oxygen (Mr = 32) in a container of volume 1000cm^3 at atmospheric pressure (101.3*10^3 Pa), what is the temperature of the gas in Celsius? R=8.314


How can I find out the Young's modulus of a material?


How do I derive Kepler's 3rd law using Newton's Law of gravitation, in the case of a circular orbit?


What is the difference between a scalar and a vector?