Find the values of X and Y from the simultaneous equations: 1) 2x + 5y = 33 2) x + 3y = 19

  1. 2x + 5y = 33 2) x + 3y = 19
    multiply equation 2 by a factor of 2 giving you 2x + 6y = 38 Your two equation are now: 1) 2x + 5y = 33 3) 2x + 6y = 38
    Subtract 3 from 1 to eliminate the x's Giving you Y = 5
    Now, as you know Y = 5 replace Y in either of the original equations to get your vaule for X. Here we will choose equation 2
    If Y = 5
    X + 3(5) = 19X = 19 - 15 X = 4
CC

Related Maths GCSE answers

All answers ▸

How can i solve the following simultaneous equations? 5x + y = 4 and 3x + 2y = 5?


Expand the following (x+4)(x+2)


How do you solve a quadratic equarion


x is inversely proportional to P. When P = 6, x =2. What does x = when P = 4?