A curve is defined by the equation y = (x + 3)(x – 4). Find the coordinates of the turning point of the curve.

The turning point of a curve is the point at which it will turn, therefore, either the maximum or minimum point. Firstly, you need to expand out the brackets so the equation looks like a standard curve equation. When expanded, the equation will be y = x2 – x – 12. The turning point will be when dy/dx is equal to 0.Therefore when the curve equation is differentiated you get 2x - 1 . Set this to 0.When solved, x will equal 0.5 . This is the x coordinate of the turning point. You need to find the y coordinate as well. To do this, fill 0.5 back into the original curve equation where an x is. The equation will now read, y = 0.25 - 0.5 - 12 . Y will equal -12.25 . Therefore the turning point will be at (0.5, -12.25) . You have now finished the question.

CM
Answered by Clare M. Further Mathematics tutor

2934 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

How to solve the inequality 1 - 2(x - 3) > 4x


Consider the Matrix M (below). Find the determiannt of the matrix M by using; (a) cofactor expansion along the first row, (b) cofactor expansion along the second column


The line y = 3x-4 intersects the curve y = x^2 - a, where a is an unknown constant number. Find all possible values of a.


Work out the gradient of the curve y=x^3(x-3) at the point (3,17)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences