ln(2x^2 + 9x – 5) = 1 + ln(x^2 + 2x – 15). Express x in terms of e

ln(2x²+ 9x – 5) = 1 + ln(x² + 2x – 15)ln(2x²+ 9x – 5) – ln(x² + 2x – 15)= 1 ln((2x²+ 9x – 5)/(x² + 2x – 15)) = 1(2x²+ 9x – 5)/(x² + 2x – 15) = e(2x – 1)(x + 5)/(x + 5)(x – 3) = e (2x – 1)/(x – 3) = e2x – 1 = e(x – 3)2x – 1 = ex – 3e2x – ex = 1 – 3ex(2 – e) = 1 – 3ex = (1 – 3e)/(2 – e)