How can you solve an equation with unknowns in the denominators?

First, you should make it so that each fraction has a common denominator. This will usually be done by multiplying the numerator and the denominator of the fraction by the same expression (this is acceptable as it is the same as multiplying by 1) so that the denominator of the fraction you are manipulating is the same as the denominator you are trying to achieve. Once all the fractions in your equation have a common denominator you need to simplify the equation by making sure you deal with any operators (eg. + or -). Once you have done this you can take away the denominator from all the fractions in your equation leaving you with a clean algebraic equation that should be relatively easy to solve using core algrebraic principles

JR

Related Maths GCSE answers

All answers ▸

For which values of x is x^2 - 5x + 6 < 0 true?


expand the brackets (x+5)(x+3) furthermore what are the two values of x


Solve the following set of simultaneous equations: 3x + y = 11, 2x + y = 8


A ball, dropped vertically, falls d metres in t seconds. d is proportional to the square of t. The ball drops 45 metres in the first 3 seconds. How far does the ball drop in the next 7 seconds?