Differentiate the equation y^2 + y = x^3 + 2x

To answer this question you must use implicit differentiation due to there being both x and y terms. Consequently you must differentiate each term individually as you would usually (by multiplying by the power and taking one off the power) but for the y terms due to chain rule the differentiated term must also be multiplied by dy/dx. Consequently the answer becomes: 2y*dy/dx + dy/dx = 3x^2 + 2. The equation must then be rearranged to make dy/dx the subject dy/dx (2y + 1) = 3x^2 + 2 Therefore dy/dx = (3x^2 + 2)/(2y+1)

DW

Related Maths A Level answers

All answers ▸

Given that y=4x^3-(5/x^2) what is dy/dx in it's simplest form?


How do we work out the asymptotes of the graph y=1/x -5


Solve 2sec^2(x) = 3 + tan(x) for 0 < x <pi/2


How do you find (and simplify) an expression, in terms of n, for the sum of the first n terms of the series 5 + 8 + 11 + 14 + ... ?