log3 (9y + b) – log3 (2y – b) = 2, Find y in terms of b.

Use laws of logarithms to simplify.Log₃((9y+b)/(2y-b)) = 2(9y+b)/(2y-b) = 3²(9y+b) = 9(2y-b)9y+b = 18y-9bCollect terms.9y = 10by = 10b/9