What is the centre and radius of the circle with the equation x(x-2)+y(y+6)+4=0 ?

x(x-4)+y(y+6)+4=0x^2-4x+y^2+6y+4=0x^2-4x+4+y^2+6y+9=9(x-2)^2+(y+3)^2=9=3^2centre (2,-3) radius 3

LW
Answered by Lauren W. Maths tutor

3229 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How can you remember what sin(x) and cos(x) differentiate or integrate to?


Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2


Find the area under the curve y = sin(2x) + cos(x) between 0 and pi/2


Using the trigonometric identity for tan(A + B), prove that tan(3x)=(3tan(x)-tan^3(x))/(1-3tan^2(x))


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning