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What is the centre and radius of the circle with the equation x(x-2)+y(y+6)+4=0 ?

x(x-4)+y(y+6)+4=0x^2-4x+y^2+6y+4=0x^2-4x+4+y^2+6y+9=9(x-2)^2+(y+3)^2=9=3^2centre (2,-3) radius 3

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Answered by Lauren W. • Maths tutor

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