What is the centre and radius of the circle with the equation x(x-2)+y(y+6)+4=0 ?
x(x-4)+y(y+6)+4=0x^2-4x+y^2+6y+4=0x^2-4x+4+y^2+6y+9=9(x-2)^2+(y+3)^2=9=3^2centre (2,-3) radius 3
LW
x(x-4)+y(y+6)+4=0x^2-4x+y^2+6y+4=0x^2-4x+4+y^2+6y+9=9(x-2)^2+(y+3)^2=9=3^2centre (2,-3) radius 3
