Solve these simultaneous equations. 2x + y = 18 x - y = 6

With simultaneous equations there is more than one unknown. First we’ll get one unknown on its own so we rearrange the bottom equation to get x on its own. By adding y to each side of the equation this leaves x = 6 + y. Now we can put this into the top equation to be 2(6 + y) + y =18. This can now be solved to find y. Expanding out of the brackets gives 12 + 2y + y =18. Collecting the ys gives 12 + 3y = 18. Subtract 12 from both sides leaves 3y =6 which gives y to be 2. Now we know y =2, we can put that in to one of the equations and get a value for x. The bottom equation would now read x – 2 = 6. Adding 2 to both sides now gives x = 8. Therefore the answer is x = 8, y = 2.

LS
Answered by Lizzie S. Maths tutor

6180 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express x^2+2x+4 in the form (x+a)^2 + b, hence find the stationary point of the curve.


Find the values of x and y when 3x+4y=18 and 4x+2y=14


The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.


Work out the value of 5^3-5^2:


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning