Differentiate z = e^(3y^2+5) with respect to y. (Hint: use chain rule.)

We can find dz/dy using chain rule dz/dy=dz/du x du/dy (1) by defining u=3y^2+5 (since the exponent of e is a function of y we call this function u) and rewrite z=e^u. Then, we find dz/du=e^u (2) and du/dy=6y (3). Now we can substitute (2) and (3) into (1) to find dz/dy=e^u 6y =6y e^(3y^2+5), where in the last line we substitute u=3y^2+5. (Ensure that you give your answer in terms of y.)

SH
Answered by Sophie H. Maths tutor

3123 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y = (x^2 + 1)^1/3


A ball is thrown in the air. The height of the ball at time t is given by: h=5+4t-2t^2. What is its maximum height? At what time does the ball reach this height?


solve dy/dx = y(sec x)^2


Q4 on 2017 Edexcel C4 paper, concerns differentiation of multiple variables.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning