If y = ln (x+1) sin x , find dy/dx
u = ln (x+1) v = sin x
du/dx = 1/(x+1) dv/dx = cos x
Therefore, by the product rule,
dy/dx = [sin x / x+1] + [ln (x+1) cos x]
EC
u = ln (x+1) v = sin x
du/dx = 1/(x+1) dv/dx = cos x
Therefore, by the product rule,
dy/dx = [sin x / x+1] + [ln (x+1) cos x]
